X is a good number if after rotating EACH digit individually by 180 degrees, we get a valid number that is different from X. A number is valid if each digit remains a digit after rotation. 0, 1, and 8 rotate to themselves; 2 and 5 rotate to each other; 6 and 9 rotate to each other, and the rest of the numbers do not rotate to any other number.

**Java Solution**

public int rotatedDigits(int N) { int result = 0; for(int i=1; i<=N; i++){ int j=i; boolean contains347 = false; boolean contains2569 = false; while(j!=0){ int mod = j%10; if(mod==2||mod==5||mod==6||mod==9){ contains2569=true; } if(mod==3||mod==4||mod==7){ contains347=true; } j=j/10; } if(!contains347&&contains2569){ result++; } } return result; } |

Name of manga in the end plz