LeetCode – Jump Game II (Java)

Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position.

Your goal is to reach the last index in the minimum number of jumps.

For example, given array A = [2,3,1,1,4], the minimum number of jumps to reach the last index is 2. (Jump 1 step from index 0 to 1, then 3 steps to the last index.)

Analysis

This is an extension of Jump Game.

The solution is similar, but we also track the maximum steps of last jump.

Java Solution

 public int jump(int[] nums) { if (nums == null || nums.length == 0) return 0;   int lastReach = 0; int reach = 0; int step = 0;   for (int i = 0; i <= reach && i < nums.length; i++) { //when last jump can not read current i, increase the step by 1 if (i > lastReach) { step++; lastReach = reach; } //update the maximal jump reach = Math.max(reach, nums[i] + i); }   if (reach < nums.length - 1) return 0;   return step; }
Category >> Algorithms >> Interview
If you want someone to read your code, please put the code inside <pre><code> and </code></pre> tags. For example:
<pre><code>
String foo = "bar";
</code></pre>
• Helen

Is this greedy algorithm?