LeetCode – Dungeon Game (Java)
Example:
2 (K) 3 3 5 10 1 10 30 5 (P)
Java Solution
This problem can be solved by using dynamic programming. We maintain a 2D table. h[i][j] is the minimum health value before he enters (i,j). h[0][0] is the value of the answer. The left part is filling in numbers to the table.
public int calculateMinimumHP(int[][] dungeon) { int m = dungeon.length; int n = dungeon[0].length; //init dp table int[][] h = new int[m][n]; h[m  1][n  1] = Math.max(1  dungeon[m  1][n  1], 1); //init last row for (int i = m  2; i >= 0; i) { h[i][n  1] = Math.max(h[i + 1][n  1]  dungeon[i][n  1], 1); } //init last column for (int j = n  2; j >= 0; j) { h[m  1][j] = Math.max(h[m  1][j + 1]  dungeon[m  1][j], 1); } //calculate dp table for (int i = m  2; i >= 0; i) { for (int j = n  2; j >= 0; j) { int down = Math.max(h[i + 1][j]  dungeon[i][j], 1); int right = Math.max(h[i][j + 1]  dungeon[i][j], 1); h[i][j] = Math.min(right, down); } } return h[0][0]; } 
<pre><code> String foo = "bar"; </code></pre>

Ing

omnomnipotent

Candis

typing..

stellari

Arnaud Hebert