Python tensorflow.python.ops.gen_nn_ops._top_kv2() Examples
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Example #1
Source File: nn_ops.py From lambda-packs with MIT License | 5 votes |
def top_k(input, k=1, sorted=True, name=None): """Finds values and indices of the `k` largest entries for the last dimension. If the input is a vector (rank-1), finds the `k` largest entries in the vector and outputs their values and indices as vectors. Thus `values[j]` is the `j`-th largest entry in `input`, and its index is `indices[j]`. For matrices (resp. higher rank input), computes the top `k` entries in each row (resp. vector along the last dimension). Thus, values.shape = indices.shape = input.shape[:-1] + [k] If two elements are equal, the lower-index element appears first. Args: input: 1-D or higher `Tensor` with last dimension at least `k`. k: 0-D `int32` `Tensor`. Number of top elements to look for along the last dimension (along each row for matrices). sorted: If true the resulting `k` elements will be sorted by the values in descending order. name: Optional name for the operation. Returns: values: The `k` largest elements along each last dimensional slice. indices: The indices of `values` within the last dimension of `input`. """ return gen_nn_ops._top_kv2(input, k=k, sorted=sorted, name=name)
Example #2
Source File: nn_ops.py From auto-alt-text-lambda-api with MIT License | 5 votes |
def top_k(input, k=1, sorted=True, name=None): """Finds values and indices of the `k` largest entries for the last dimension. If the input is a vector (rank-1), finds the `k` largest entries in the vector and outputs their values and indices as vectors. Thus `values[j]` is the `j`-th largest entry in `input`, and its index is `indices[j]`. For matrices (resp. higher rank input), computes the top `k` entries in each row (resp. vector along the last dimension). Thus, values.shape = indices.shape = input.shape[:-1] + [k] If two elements are equal, the lower-index element appears first. Args: input: 1-D or higher `Tensor` with last dimension at least `k`. k: 0-D `int32` `Tensor`. Number of top elements to look for along the last dimension (along each row for matrices). sorted: If true the resulting `k` elements will be sorted by the values in descending order. name: Optional name for the operation. Returns: values: The `k` largest elements along each last dimensional slice. indices: The indices of `values` within the last dimension of `input`. """ return gen_nn_ops._top_kv2(input, k=k, sorted=sorted, name=name)
Example #3
Source File: nn_ops.py From deep_image_model with Apache License 2.0 | 5 votes |
def top_k(input, k=1, sorted=True, name=None): """Finds values and indices of the `k` largest entries for the last dimension. If the input is a vector (rank-1), finds the `k` largest entries in the vector and outputs their values and indices as vectors. Thus `values[j]` is the `j`-th largest entry in `input`, and its index is `indices[j]`. For matrices (resp. higher rank input), computes the top `k` entries in each row (resp. vector along the last dimension). Thus, values.shape = indices.shape = input.shape[:-1] + [k] If two elements are equal, the lower-index element appears first. Args: input: 1-D or higher `Tensor` with last dimension at least `k`. k: 0-D `int32` `Tensor`. Number of top elements to look for along the last dimension (along each row for matrices). sorted: If true the resulting `k` elements will be sorted by the values in descending order. name: Optional name for the operation. Returns: values: The `k` largest elements along each last dimensional slice. indices: The indices of `values` within the last dimension of `input`. """ return gen_nn_ops._top_kv2(input, k=k, sorted=sorted, name=name)
Example #4
Source File: nn_ops.py From Serverless-Deep-Learning-with-TensorFlow-and-AWS-Lambda with MIT License | 5 votes |
def top_k(input, k=1, sorted=True, name=None): """Finds values and indices of the `k` largest entries for the last dimension. If the input is a vector (rank-1), finds the `k` largest entries in the vector and outputs their values and indices as vectors. Thus `values[j]` is the `j`-th largest entry in `input`, and its index is `indices[j]`. For matrices (resp. higher rank input), computes the top `k` entries in each row (resp. vector along the last dimension). Thus, values.shape = indices.shape = input.shape[:-1] + [k] If two elements are equal, the lower-index element appears first. Args: input: 1-D or higher `Tensor` with last dimension at least `k`. k: 0-D `int32` `Tensor`. Number of top elements to look for along the last dimension (along each row for matrices). sorted: If true the resulting `k` elements will be sorted by the values in descending order. name: Optional name for the operation. Returns: values: The `k` largest elements along each last dimensional slice. indices: The indices of `values` within the last dimension of `input`. """ return gen_nn_ops._top_kv2(input, k=k, sorted=sorted, name=name)
Example #5
Source File: nn_ops.py From keras-lambda with MIT License | 5 votes |
def top_k(input, k=1, sorted=True, name=None): """Finds values and indices of the `k` largest entries for the last dimension. If the input is a vector (rank-1), finds the `k` largest entries in the vector and outputs their values and indices as vectors. Thus `values[j]` is the `j`-th largest entry in `input`, and its index is `indices[j]`. For matrices (resp. higher rank input), computes the top `k` entries in each row (resp. vector along the last dimension). Thus, values.shape = indices.shape = input.shape[:-1] + [k] If two elements are equal, the lower-index element appears first. Args: input: 1-D or higher `Tensor` with last dimension at least `k`. k: 0-D `int32` `Tensor`. Number of top elements to look for along the last dimension (along each row for matrices). sorted: If true the resulting `k` elements will be sorted by the values in descending order. name: Optional name for the operation. Returns: values: The `k` largest elements along each last dimensional slice. indices: The indices of `values` within the last dimension of `input`. """ return gen_nn_ops._top_kv2(input, k=k, sorted=sorted, name=name)