#!/bin/python3
import itertools
import collections
def sliding_window(n, seq):
"""
Copied from toolz
https://toolz.readthedocs.io/en/latest/_modules/toolz/itertoolz.html#sliding_window
A sequence of overlapping subsequences
>>> list(sliding_window(2, [1, 2, 3, 4]))
[(1, 2), (2, 3), (3, 4)]
This function creates a sliding window suitable for transformations like
sliding means / smoothing
>>> mean = lambda seq: float(sum(seq)) / len(seq)
>>> list(map(mean, sliding_window(2, [1, 2, 3, 4])))
[1.5, 2.5, 3.5]
"""
return zip(*(collections.deque(itertools.islice(it, i), 0) or it
for i, it in enumerate(itertools.tee(seq, n))))
def birthday_chocolate(squares, day, month):
consecutive_sums = map(lambda piece: sum(piece),
sliding_window(month, squares))
birthday_bars = list(filter(lambda consecutive_sum: day == consecutive_sum,
consecutive_sums))
return len(birthday_bars)
_ = int(input().strip())
SQUARES = list(map(int, input().strip().split(' ')))
DAY, MONTH = map(int, input().strip().split(' '))
print(birthday_chocolate(SQUARES, DAY, MONTH))
