Python pkg_resources.ContextualZipFile() Examples

The following are 18 code examples of pkg_resources.ContextualZipFile(). You can vote up the ones you like or vote down the ones you don't like, and go to the original project or source file by following the links above each example. You may also want to check out all available functions/classes of the module pkg_resources , or try the search function .
Example #1
Source File: archive_util.py    From Flask-P2P with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #2
Source File: archive_util.py    From CTFCrackTools with GNU General Public License v3.0 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #3
Source File: archive_util.py    From aws-kube-codesuite with Apache License 2.0 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #4
Source File: archive_util.py    From CTFCrackTools-V2 with GNU General Public License v3.0 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #5
Source File: archive_util.py    From syntheticmass with Apache License 2.0 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #6
Source File: archive_util.py    From PhonePi_SampleServer with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #7
Source File: archive_util.py    From datafari with Apache License 2.0 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #8
Source File: archive_util.py    From Ansible with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #9
Source File: archive_util.py    From ImageFusion with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #10
Source File: archive_util.py    From jbox with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #11
Source File: archive_util.py    From Financial-Portfolio-Flask with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #12
Source File: archive_util.py    From telegram-robot-rss with Mozilla Public License 2.0 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #13
Source File: archive_util.py    From Safejumper-for-Desktop with GNU General Public License v2.0 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #14
Source File: archive_util.py    From oss-ftp with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                f = open(target,'wb')
                try:
                    f.write(data)
                finally:
                    f.close()
                    del data
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #15
Source File: archive_util.py    From kobo-predict with BSD 2-Clause "Simplified" License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #16
Source File: archive_util.py    From lambda-chef-node-cleanup with Apache License 2.0 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #17
Source File: archive_util.py    From python-netsurv with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)
Example #18
Source File: archive_util.py    From python-netsurv with MIT License 5 votes vote down vote up 
def unpack_zipfile(filename, extract_dir, progress_filter=default_filter):
    """Unpack zip `filename` to `extract_dir`

    Raises ``UnrecognizedFormat`` if `filename` is not a zipfile (as determined
    by ``zipfile.is_zipfile()``).  See ``unpack_archive()`` for an explanation
    of the `progress_filter` argument.
    """

    if not zipfile.is_zipfile(filename):
        raise UnrecognizedFormat("%s is not a zip file" % (filename,))

    with ContextualZipFile(filename) as z:
        for info in z.infolist():
            name = info.filename

            # don't extract absolute paths or ones with .. in them
            if name.startswith('/') or '..' in name.split('/'):
                continue

            target = os.path.join(extract_dir, *name.split('/'))
            target = progress_filter(name, target)
            if not target:
                continue
            if name.endswith('/'):
                # directory
                ensure_directory(target)
            else:
                # file
                ensure_directory(target)
                data = z.read(info.filename)
                with open(target, 'wb') as f:
                    f.write(data)
            unix_attributes = info.external_attr >> 16
            if unix_attributes:
                os.chmod(target, unix_attributes)