Python email.Utils.parsedate_tz() Examples

The following are 30 code examples of email.Utils.parsedate_tz(). You can vote up the ones you like or vote down the ones you don't like, and go to the original project or source file by following the links above each example. You may also want to check out all available functions/classes of the module email.Utils , or try the search function

Example #1

Source File: http.py From data with GNU General Public License v3.0

5 votes

def parse_date(value):
    """Parse one of the following date formats into a datetime object:

    .. sourcecode:: text

        Sun, 06 Nov 1994 08:49:37 GMT  ; RFC 822, updated by RFC 1123
        Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
        Sun Nov  6 08:49:37 1994       ; ANSI C's asctime() format

    If parsing fails the return value is `None`.

    :param value: a string with a supported date format.
    :return: a :class:`datetime.datetime` object.
    """
    if value:
        t = parsedate_tz(value.strip())
        if t is not None:
            try:
                year = t[0]
                # unfortunately that function does not tell us if two digit
                # years were part of the string, or if they were prefixed
                # with two zeroes.  So what we do is to assume that 69-99
                # refer to 1900, and everything below to 2000
                if year >= 0 and year <= 68:
                    year += 2000
                elif year >= 69 and year <= 99:
                    year += 1900
                return datetime(*((year,) + t[1:7])) - \
                    timedelta(seconds=t[-1] or 0)
            except (ValueError, OverflowError):
                return None

Example #2

Source File: test_email.py From medicare-demo with Apache License 2.0

5 votes

def test_parsedate_acceptable_to_time_functions(self):
        eq = self.assertEqual
        timetup = Utils.parsedate('5 Feb 2003 13:47:26 -0800')
        t = int(time.mktime(timetup))
        eq(time.localtime(t)[:6], timetup[:6])
        eq(int(time.strftime('%Y', timetup)), 2003)
        timetup = Utils.parsedate_tz('5 Feb 2003 13:47:26 -0800')
        t = int(time.mktime(timetup[:9]))
        eq(time.localtime(t)[:6], timetup[:6])
        eq(int(time.strftime('%Y', timetup[:9])), 2003)

Example #3

Source File: http.py From cloud-playground with Apache License 2.0

5 votes

def parse_date(value):
    """Parse one of the following date formats into a datetime object:

    .. sourcecode:: text

        Sun, 06 Nov 1994 08:49:37 GMT  ; RFC 822, updated by RFC 1123
        Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
        Sun Nov  6 08:49:37 1994       ; ANSI C's asctime() format

    If parsing fails the return value is `None`.

    :param value: a string with a supported date format.
    :return: a :class:`datetime.datetime` object.
    """
    if value:
        t = parsedate_tz(value.strip())
        if t is not None:
            try:
                year = t[0]
                # unfortunately that function does not tell us if two digit
                # years were part of the string, or if they were prefixed
                # with two zeroes.  So what we do is to assume that 69-99
                # refer to 1900, and everything below to 2000
                if year >= 0 and year <= 68:
                    year += 2000
                elif year >= 69 and year <= 99:
                    year += 1900
                return datetime(*((year,) + t[1:7])) - \
                       timedelta(seconds=t[-1] or 0)
            except (ValueError, OverflowError):
                return None

Example #4

Source File: http.py From syntheticmass with Apache License 2.0

5 votes

def parse_date(value):
    """Parse one of the following date formats into a datetime object:

    .. sourcecode:: text

        Sun, 06 Nov 1994 08:49:37 GMT  ; RFC 822, updated by RFC 1123
        Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
        Sun Nov  6 08:49:37 1994       ; ANSI C's asctime() format

    If parsing fails the return value is `None`.

    :param value: a string with a supported date format.
    :return: a :class:`datetime.datetime` object.
    """
    if value:
        t = parsedate_tz(value.strip())
        if t is not None:
            try:
                year = t[0]
                # unfortunately that function does not tell us if two digit
                # years were part of the string, or if they were prefixed
                # with two zeroes.  So what we do is to assume that 69-99
                # refer to 1900, and everything below to 2000
                if year >= 0 and year <= 68:
                    year += 2000
                elif year >= 69 and year <= 99:
                    year += 1900
                return datetime(*((year,) + t[1:7])) - \
                    timedelta(seconds=t[-1] or 0)
            except (ValueError, OverflowError):
                return None

Example #5

Source File: http.py From arithmancer with Apache License 2.0

5 votes

def parse_date(value):
    """Parse one of the following date formats into a datetime object:

    .. sourcecode:: text

        Sun, 06 Nov 1994 08:49:37 GMT  ; RFC 822, updated by RFC 1123
        Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
        Sun Nov  6 08:49:37 1994       ; ANSI C's asctime() format

    If parsing fails the return value is `None`.

    :param value: a string with a supported date format.
    :return: a :class:`datetime.datetime` object.
    """
    if value:
        t = parsedate_tz(value.strip())
        if t is not None:
            try:
                year = t[0]
                # unfortunately that function does not tell us if two digit
                # years were part of the string, or if they were prefixed
                # with two zeroes.  So what we do is to assume that 69-99
                # refer to 1900, and everything below to 2000
                if year >= 0 and year <= 68:
                    year += 2000
                elif year >= 69 and year <= 99:
                    year += 1900
                return datetime(*((year,) + t[1:7])) - \
                       timedelta(seconds=t[-1] or 0)
            except (ValueError, OverflowError):
                return None

Example #6

Source File: http.py From appengine-try-python-flask with Apache License 2.0

5 votes

def parse_date(value):
    """Parse one of the following date formats into a datetime object:

    .. sourcecode:: text

        Sun, 06 Nov 1994 08:49:37 GMT  ; RFC 822, updated by RFC 1123
        Sunday, 06-Nov-94 08:49:37 GMT ; RFC 850, obsoleted by RFC 1036
        Sun Nov  6 08:49:37 1994       ; ANSI C's asctime() format

    If parsing fails the return value is `None`.

    :param value: a string with a supported date format.
    :return: a :class:`datetime.datetime` object.
    """
    if value:
        t = parsedate_tz(value.strip())
        if t is not None:
            try:
                year = t[0]
                # unfortunately that function does not tell us if two digit
                # years were part of the string, or if they were prefixed
                # with two zeroes.  So what we do is to assume that 69-99
                # refer to 1900, and everything below to 2000
                if year >= 0 and year <= 68:
                    year += 2000
                elif year >= 69 and year <= 99:
                    year += 1900
                return datetime(*((year,) + t[1:7])) - \
                       timedelta(seconds=t[-1] or 0)
            except (ValueError, OverflowError):
                return None

Example #7