import java.util.ArrayDeque; import java.util.ArrayList; import java.util.Arrays; import java.util.Deque; import java.util.List; import java.util.Stack; public class Solution { public List<List<Integer>> threeSum(int[] nums) { List<List<Integer>> res = new ArrayList<>(); int len = nums.length; // 特判 1 if (len < 3) { return res; } // 排序是去重复的前提 Arrays.sort(nums); // [0, 1, 2, 3] 4 for (int i = 0; i < len - 2; i++) { // 特判 2 if (nums[i] > 0) { break; } // 剪枝 1 if (i > 0 && nums[i] == nums[i - 1]) { continue; } int left = i + 1; int right = len - 1; // 注意:这里是严格小于 while (left < right) { int sum = nums[i] + nums[left] + nums[right]; if (sum == 0) { List<Integer> cur = new ArrayList<>(); cur.add(nums[i]); cur.add(nums[left]); cur.add(nums[right]); res.add(cur); // 剪枝 2 while (left < right && nums[left + 1] == nums[left]) { left++; } while (left < right && nums[right - 1] == nums[right]) { right--; } left++; right--; } else if (sum > 0) { // 后面的数太大了,让它往前走一步试试看 right--; } else { // sum < 0, 前面的数太小了,让它往后走一步试试看 left++; } } } return res; } public static void main(String[] args) { int[] nums = {0, 0, 0, 0}; Solution solution3 = new Solution(); List<List<Integer>> res = solution3.threeSum(nums); res.forEach(System.out::println); List<Integer> res1 = new ArrayList<>(); Deque<Integer> stack = new ArrayDeque<Integer>(); } }