# Java Code Examples for java.awt.geom.AffineTransform#TYPE_GENERAL_SCALE

The following examples show how to use
java.awt.geom.AffineTransform#TYPE_GENERAL_SCALE .
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Example 1

Source Project: dragonwell8_jdk File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

private float userSpaceLineWidth(AffineTransform at, float lw) { double widthScale; if ((at.getType() & (AffineTransform.TYPE_GENERAL_TRANSFORM | AffineTransform.TYPE_GENERAL_SCALE)) != 0) { widthScale = Math.sqrt(at.getDeterminant()); } else { /* First calculate the "maximum scale" of this transform. */ double A = at.getScaleX(); // m00 double C = at.getShearX(); // m01 double B = at.getShearY(); // m10 double D = at.getScaleY(); // m11 /* * Given a 2 x 2 affine matrix [ A B ] such that * [ C D ] * v' = [x' y'] = [Ax + Cy, Bx + Dy], we want to * find the maximum magnitude (norm) of the vector v' * with the constraint (x^2 + y^2 = 1). * The equation to maximize is * |v'| = sqrt((Ax+Cy)^2+(Bx+Dy)^2) * or |v'| = sqrt((AA+BB)x^2 + 2(AC+BD)xy + (CC+DD)y^2). * Since sqrt is monotonic we can maximize |v'|^2 * instead and plug in the substitution y = sqrt(1 - x^2). * Trigonometric equalities can then be used to get * rid of most of the sqrt terms. */ double EA = A*A + B*B; // x^2 coefficient double EB = 2*(A*C + B*D); // xy coefficient double EC = C*C + D*D; // y^2 coefficient /* * There is a lot of calculus omitted here. * * Conceptually, in the interests of understanding the * terms that the calculus produced we can consider * that EA and EC end up providing the lengths along * the major axes and the hypot term ends up being an * adjustment for the additional length along the off-axis * angle of rotated or sheared ellipses as well as an * adjustment for the fact that the equation below * averages the two major axis lengths. (Notice that * the hypot term contains a part which resolves to the * difference of these two axis lengths in the absence * of rotation.) * * In the calculus, the ratio of the EB and (EA-EC) terms * ends up being the tangent of 2*theta where theta is * the angle that the long axis of the ellipse makes * with the horizontal axis. Thus, this equation is * calculating the length of the hypotenuse of a triangle * along that axis. */ double hypot = Math.sqrt(EB*EB + (EA-EC)*(EA-EC)); /* sqrt omitted, compare to squared limits below. */ double widthsquared = ((EA + EC + hypot)/2.0); widthScale = Math.sqrt(widthsquared); } return (float) (lw / widthScale); }

Example 2

Source Project: TencentKona-8 File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 3

Source Project: jdk8u60 File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 4

Source Project: openjdk-jdk8u File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 5

Source Project: openjdk-jdk8u File: MarlinRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

private final float userSpaceLineWidth(AffineTransform at, float lw) { float widthScale; if (at == null) { widthScale = 1.0f; } else if ((at.getType() & (AffineTransform.TYPE_GENERAL_TRANSFORM | AffineTransform.TYPE_GENERAL_SCALE)) != 0) { widthScale = (float)Math.sqrt(at.getDeterminant()); } else { // First calculate the "maximum scale" of this transform. double A = at.getScaleX(); // m00 double C = at.getShearX(); // m01 double B = at.getShearY(); // m10 double D = at.getScaleY(); // m11 /* * Given a 2 x 2 affine matrix [ A B ] such that * [ C D ] * v' = [x' y'] = [Ax + Cy, Bx + Dy], we want to * find the maximum magnitude (norm) of the vector v' * with the constraint (x^2 + y^2 = 1). * The equation to maximize is * |v'| = sqrt((Ax+Cy)^2+(Bx+Dy)^2) * or |v'| = sqrt((AA+BB)x^2 + 2(AC+BD)xy + (CC+DD)y^2). * Since sqrt is monotonic we can maximize |v'|^2 * instead and plug in the substitution y = sqrt(1 - x^2). * Trigonometric equalities can then be used to get * rid of most of the sqrt terms. */ double EA = A*A + B*B; // x^2 coefficient double EB = 2.0*(A*C + B*D); // xy coefficient double EC = C*C + D*D; // y^2 coefficient /* * There is a lot of calculus omitted here. * * Conceptually, in the interests of understanding the * terms that the calculus produced we can consider * that EA and EC end up providing the lengths along * the major axes and the hypot term ends up being an * adjustment for the additional length along the off-axis * angle of rotated or sheared ellipses as well as an * adjustment for the fact that the equation below * averages the two major axis lengths. (Notice that * the hypot term contains a part which resolves to the * difference of these two axis lengths in the absence * of rotation.) * * In the calculus, the ratio of the EB and (EA-EC) terms * ends up being the tangent of 2*theta where theta is * the angle that the long axis of the ellipse makes * with the horizontal axis. Thus, this equation is * calculating the length of the hypotenuse of a triangle * along that axis. */ double hypot = Math.sqrt(EB*EB + (EA-EC)*(EA-EC)); // sqrt omitted, compare to squared limits below. double widthsquared = ((EA + EC + hypot)/2.0); widthScale = (float)Math.sqrt(widthsquared); } return (lw / widthScale); }

Example 6

Source Project: openjdk-jdk8u-backup File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 7

Source Project: Bytecoder File: DMarlinRenderingEngine.java License: Apache License 2.0 | 4 votes |

private double userSpaceLineWidth(AffineTransform at, double lw) { double widthScale; if (at == null) { widthScale = 1.0d; } else if ((at.getType() & (AffineTransform.TYPE_GENERAL_TRANSFORM | AffineTransform.TYPE_GENERAL_SCALE)) != 0) { // Determinant may be negative (flip), use its absolute value: widthScale = Math.sqrt(Math.abs(at.getDeterminant())); } else { // First calculate the "maximum scale" of this transform. double A = at.getScaleX(); // m00 double C = at.getShearX(); // m01 double B = at.getShearY(); // m10 double D = at.getScaleY(); // m11 /* * Given a 2 x 2 affine matrix [ A B ] such that * [ C D ] * v' = [x' y'] = [Ax + Cy, Bx + Dy], we want to * find the maximum magnitude (norm) of the vector v' * with the constraint (x^2 + y^2 = 1). * The equation to maximize is * |v'| = sqrt((Ax+Cy)^2+(Bx+Dy)^2) * or |v'| = sqrt((AA+BB)x^2 + 2(AC+BD)xy + (CC+DD)y^2). * Since sqrt is monotonic we can maximize |v'|^2 * instead and plug in the substitution y = sqrt(1 - x^2). * Trigonometric equalities can then be used to get * rid of most of the sqrt terms. */ double EA = A*A + B*B; // x^2 coefficient double EB = 2.0d * (A*C + B*D); // xy coefficient double EC = C*C + D*D; // y^2 coefficient /* * There is a lot of calculus omitted here. * * Conceptually, in the interests of understanding the * terms that the calculus produced we can consider * that EA and EC end up providing the lengths along * the major axes and the hypot term ends up being an * adjustment for the additional length along the off-axis * angle of rotated or sheared ellipses as well as an * adjustment for the fact that the equation below * averages the two major axis lengths. (Notice that * the hypot term contains a part which resolves to the * difference of these two axis lengths in the absence * of rotation.) * * In the calculus, the ratio of the EB and (EA-EC) terms * ends up being the tangent of 2*theta where theta is * the angle that the long axis of the ellipse makes * with the horizontal axis. Thus, this equation is * calculating the length of the hypotenuse of a triangle * along that axis. */ double hypot = Math.sqrt(EB*EB + (EA-EC)*(EA-EC)); // sqrt omitted, compare to squared limits below. double widthsquared = ((EA + EC + hypot) / 2.0d); widthScale = Math.sqrt(widthsquared); } return (lw / widthScale); }

Example 8

Source Project: Bytecoder File: MarlinRenderingEngine.java License: Apache License 2.0 | 4 votes |

private float userSpaceLineWidth(AffineTransform at, float lw) { float widthScale; if (at == null) { widthScale = 1.0f; } else if ((at.getType() & (AffineTransform.TYPE_GENERAL_TRANSFORM | AffineTransform.TYPE_GENERAL_SCALE)) != 0) { // Determinant may be negative (flip), use its absolute value: widthScale = (float)Math.sqrt(Math.abs(at.getDeterminant())); } else { // First calculate the "maximum scale" of this transform. double A = at.getScaleX(); // m00 double C = at.getShearX(); // m01 double B = at.getShearY(); // m10 double D = at.getScaleY(); // m11 /* * Given a 2 x 2 affine matrix [ A B ] such that * [ C D ] * v' = [x' y'] = [Ax + Cy, Bx + Dy], we want to * find the maximum magnitude (norm) of the vector v' * with the constraint (x^2 + y^2 = 1). * The equation to maximize is * |v'| = sqrt((Ax+Cy)^2+(Bx+Dy)^2) * or |v'| = sqrt((AA+BB)x^2 + 2(AC+BD)xy + (CC+DD)y^2). * Since sqrt is monotonic we can maximize |v'|^2 * instead and plug in the substitution y = sqrt(1 - x^2). * Trigonometric equalities can then be used to get * rid of most of the sqrt terms. */ double EA = A*A + B*B; // x^2 coefficient double EB = 2.0d * (A*C + B*D); // xy coefficient double EC = C*C + D*D; // y^2 coefficient /* * There is a lot of calculus omitted here. * * Conceptually, in the interests of understanding the * terms that the calculus produced we can consider * that EA and EC end up providing the lengths along * the major axes and the hypot term ends up being an * adjustment for the additional length along the off-axis * angle of rotated or sheared ellipses as well as an * adjustment for the fact that the equation below * averages the two major axis lengths. (Notice that * the hypot term contains a part which resolves to the * difference of these two axis lengths in the absence * of rotation.) * * In the calculus, the ratio of the EB and (EA-EC) terms * ends up being the tangent of 2*theta where theta is * the angle that the long axis of the ellipse makes * with the horizontal axis. Thus, this equation is * calculating the length of the hypotenuse of a triangle * along that axis. */ double hypot = Math.sqrt(EB*EB + (EA-EC)*(EA-EC)); // sqrt omitted, compare to squared limits below. double widthsquared = ((EA + EC + hypot) / 2.0d); widthScale = (float)Math.sqrt(widthsquared); } return (lw / widthScale); }

Example 9

Source Project: openjdk-jdk9 File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 10

Source Project: openjdk-jdk9 File: MarlinRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 11

Source Project: jdk8u-jdk File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 12

Source Project: hottub File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 13

Source Project: openjdk-8-source File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 14

Source Project: openjdk-8 File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 15

Source Project: jdk8u_jdk File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 16

Source Project: jdk8u_jdk File: DMarlinRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

private double userSpaceLineWidth(AffineTransform at, double lw) { double widthScale; if (at == null) { widthScale = 1.0d; } else if ((at.getType() & (AffineTransform.TYPE_GENERAL_TRANSFORM | AffineTransform.TYPE_GENERAL_SCALE)) != 0) { widthScale = Math.sqrt(at.getDeterminant()); } else { // First calculate the "maximum scale" of this transform. double A = at.getScaleX(); // m00 double C = at.getShearX(); // m01 double B = at.getShearY(); // m10 double D = at.getScaleY(); // m11 /* * Given a 2 x 2 affine matrix [ A B ] such that * [ C D ] * v' = [x' y'] = [Ax + Cy, Bx + Dy], we want to * find the maximum magnitude (norm) of the vector v' * with the constraint (x^2 + y^2 = 1). * The equation to maximize is * |v'| = sqrt((Ax+Cy)^2+(Bx+Dy)^2) * or |v'| = sqrt((AA+BB)x^2 + 2(AC+BD)xy + (CC+DD)y^2). * Since sqrt is monotonic we can maximize |v'|^2 * instead and plug in the substitution y = sqrt(1 - x^2). * Trigonometric equalities can then be used to get * rid of most of the sqrt terms. */ double EA = A*A + B*B; // x^2 coefficient double EB = 2.0d * (A*C + B*D); // xy coefficient double EC = C*C + D*D; // y^2 coefficient /* * There is a lot of calculus omitted here. * * Conceptually, in the interests of understanding the * terms that the calculus produced we can consider * that EA and EC end up providing the lengths along * the major axes and the hypot term ends up being an * adjustment for the additional length along the off-axis * angle of rotated or sheared ellipses as well as an * adjustment for the fact that the equation below * averages the two major axis lengths. (Notice that * the hypot term contains a part which resolves to the * difference of these two axis lengths in the absence * of rotation.) * * In the calculus, the ratio of the EB and (EA-EC) terms * ends up being the tangent of 2*theta where theta is * the angle that the long axis of the ellipse makes * with the horizontal axis. Thus, this equation is * calculating the length of the hypotenuse of a triangle * along that axis. */ double hypot = Math.sqrt(EB*EB + (EA-EC)*(EA-EC)); // sqrt omitted, compare to squared limits below. double widthsquared = ((EA + EC + hypot) / 2.0d); widthScale = Math.sqrt(widthsquared); } return (lw / widthScale); }

Example 17

Source Project: jdk8u_jdk File: MarlinRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

private float userSpaceLineWidth(AffineTransform at, float lw) { float widthScale; if (at == null) { widthScale = 1.0f; } else if ((at.getType() & (AffineTransform.TYPE_GENERAL_TRANSFORM | AffineTransform.TYPE_GENERAL_SCALE)) != 0) { widthScale = (float)Math.sqrt(at.getDeterminant()); } else { // First calculate the "maximum scale" of this transform. double A = at.getScaleX(); // m00 double C = at.getShearX(); // m01 double B = at.getShearY(); // m10 double D = at.getScaleY(); // m11 /* * Given a 2 x 2 affine matrix [ A B ] such that * [ C D ] * v' = [x' y'] = [Ax + Cy, Bx + Dy], we want to * find the maximum magnitude (norm) of the vector v' * with the constraint (x^2 + y^2 = 1). * The equation to maximize is * |v'| = sqrt((Ax+Cy)^2+(Bx+Dy)^2) * or |v'| = sqrt((AA+BB)x^2 + 2(AC+BD)xy + (CC+DD)y^2). * Since sqrt is monotonic we can maximize |v'|^2 * instead and plug in the substitution y = sqrt(1 - x^2). * Trigonometric equalities can then be used to get * rid of most of the sqrt terms. */ double EA = A*A + B*B; // x^2 coefficient double EB = 2.0d * (A*C + B*D); // xy coefficient double EC = C*C + D*D; // y^2 coefficient /* * There is a lot of calculus omitted here. * * Conceptually, in the interests of understanding the * terms that the calculus produced we can consider * that EA and EC end up providing the lengths along * the major axes and the hypot term ends up being an * adjustment for the additional length along the off-axis * angle of rotated or sheared ellipses as well as an * adjustment for the fact that the equation below * averages the two major axis lengths. (Notice that * the hypot term contains a part which resolves to the * difference of these two axis lengths in the absence * of rotation.) * * In the calculus, the ratio of the EB and (EA-EC) terms * ends up being the tangent of 2*theta where theta is * the angle that the long axis of the ellipse makes * with the horizontal axis. Thus, this equation is * calculating the length of the hypotenuse of a triangle * along that axis. */ double hypot = Math.sqrt(EB*EB + (EA-EC)*(EA-EC)); // sqrt omitted, compare to squared limits below. double widthsquared = ((EA + EC + hypot) / 2.0d); widthScale = (float)Math.sqrt(widthsquared); } return (lw / widthScale); }

Example 18

Source Project: jdk8u-jdk File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |

Example 19

Source Project: jdk8u-dev-jdk File: PiscesRenderingEngine.java License: GNU General Public License v2.0 | 4 votes |