LeetCode – First Bad Version (Java)

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

Java Solution 1 - Recurisve

public int firstBadVersion(int n) {
    return helper(1, n);
public int helper(int i, int j){
    int m = i + (j-i)/2;
        return i;
        return helper(i, m);
        return helper(m+1, j); //not bad, left --> m+1

Java Solution 2 - Iterative

public int firstBadVersion(int n) {
    int i = 1, j = n;
    while (i < j) {
        int m = i + (j-i) / 2;
        if (isBadVersion(m)) {
            j = m;
        } else {
            i = m+1;
    if (isBadVersion(i)) {
        return i;
    return j;
Category >> Algorithms  
If you want someone to read your code, please put the code inside <pre><code> and </code></pre> tags. For example:
String foo = "bar";