LeetCode – Rotate Image (Java)

You are given an n x n 2D matrix representing an image.

Rotate the image by 90 degrees (clockwise).

Follow up:
Could you do this in-place?

In-place Solution

By using the relation "matrix[i][j] = matrix[n-1-j][i]", we can loop through the matrix.

public void rotate(int[][] matrix) {
	int n = matrix.length;
	for (int i = 0; i < n / 2; i++) {
		for (int j = 0; j < Math.ceil(((double) n) / 2.); j++) {
			int temp = matrix[i][j];
			matrix[i][j] = matrix[n-1-j][i];
			matrix[n-1-j][i] = matrix[n-1-i][n-1-j];
			matrix[n-1-i][n-1-j] = matrix[j][n-1-i];
			matrix[j][n-1-i] = temp;
Category >> Algorithms  
If you want someone to read your code, please put the code inside <pre><code> and </code></pre> tags. For example:
String foo = "bar";
  • NightCoder

    int length = matrix.length-1;
    System.out.println("len "+matrix.length);
    for (int i = 0; i <= (length)/2; i++) {
    for (int j = i; j < length-i; j++) {

    int temp = matrix[i][j];

    matrix[i][j] = matrix[length-j][i];
    matrix[length-j][i] = matrix[length-i][length-j];
    matrix[length-i][length-j] = matrix[j][length-i];
    matrix[j][length-i] = temp;

  • Guest

    why Math.ceil(((double) n) /2.) is used?

  • hina jain

    I think the j should be initialized to i instead of 0 in the second for loop.

  • svGuy

    transpose the matrix and swap rows

  • svGuy

    its easier to transpose the matrix first and then swap columns for clockwise rotation.

  • Ivy G

    You can replace “Math.ceil(((double) n) / 2.” with “(n+1)/2”

  • Chen Chen

    Great! Thanks for sharing.

  • my boo

    my bad, I got the axis messed up.

  • my boo

    Your algorithm counter rotate the image instead of clock wise rotate.

  • Guest

    If I is your matrix

    for i in range(n):

    print a

  • A Programmer

    how would you do it counter clockwise?

  • kinshuk chandra

    I liked the inplace solution. I have also done the same thing here – http://k2code.blogspot.in/2014/03/rotate-n-n-matrix-by-90-degrees.html