# LeetCode – Self Crossing (Java)

Analysis

This problem can be easily solved if the three self crossing cases are summarized well. Here are the three self crossing cases. There are no other self crossing situations based on the restrictions of counter-clockwise.

Java Solution

Writing the solution is straightforward once the 3 self crossing cases are identified.

```public boolean isSelfCrossing(int[] x) { if(x==null || x.length<=3) return false;   for(int i=3; i<x.length; i++){ if(x[i-3] >= x[i-1] && x[i-2]<=x[i]){ return true; }   if(i>=4 && x[i-4]+x[i]>=x[i-2] && x[i-3]==x[i-1]) { return true; }   if(i>=5 && x[i-5]<=x[i-3] && x[i]<=x[i-2]&& x[i-1]<=x[i-3] && x[i-4]<=x[i-2] && x[i-1]>=x[i-3]-x[i-5] && x[i]>=x[i-2]-x[i-4]){ return true; } }   return false; }```
Category >> Algorithms
If you want someone to read your code, please put the code inside <pre><code> and </code></pre> tags. For example:
```<pre><code>
String foo = "bar";
</code></pre>
```
• dharmendra patel

I think there can be more scenarios. what do you think?