LeetCode – Bitwise AND of Numbers Range (Java)
Given a range [m, n] where 0 <= m <= n <= 2147483647, return the bitwise AND of all numbers in this range, inclusive. For example, given the range [5, 7], you should return 4. Java Solution
The key to solve this problem is bitwise AND consecutive numbers. You can use the following example to walk through the code.
8 4 2 1  5  0 1 0 1 6  0 1 1 0 7  0 1 1 1
public int rangeBitwiseAnd(int m, int n) { while (n > m) { n = n & n  1; } return m & n; } 
<pre><code> String foo = "bar"; </code></pre>

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