LeetCode – 3Sum Closest (Java)
Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {1 2 1 4}, and target = 1. The sum that is closest to the target is 2. (1 + 2 + 1 = 2).
Analysis
This problem is similar to 2 Sum. This kind of problem can be solved by using a similar approach, i.e., two pointers from both left and right.
Java Solution
public int threeSumClosest(int[] nums, int target) { int min = Integer.MAX_VALUE; int result = 0; Arrays.sort(nums); for (int i = 0; i < nums.length; i++) { int j = i + 1; int k = nums.length  1; while (j < k) { int sum = nums[i] + nums[j] + nums[k]; int diff = Math.abs(sum  target); if(diff == 0) return sum; if (diff < min) { min = diff; result = sum; } if (sum <= target) { j++; } else { k; } } } return result; } 
Time Complexity is O(n^2).
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