Leetcode – Add Two Numbers (Java)

You are given two linked lists representing two non-negative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8

Java Solution

public class Solution {
    public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
       int carry =0;
        ListNode newHead = new ListNode(0);
        ListNode p1 = l1, p2 = l2, p3=newHead;
        while(p1 != null || p2 != null){
            if(p1 != null){
                carry += p1.val;
                p1 = p1.next;
            if(p2 != null){
                carry += p2.val;
                p2 = p2.next;
            p3.next = new ListNode(carry%10);
            p3 = p3.next;
            carry /= 10;
            p3.next=new ListNode(1);
        return newHead.next;

What if the digits are stored in regular order instead of reversed order?

Answer: We can simple reverse the list, calculate the result, and reverse the result.

Category >> Algorithms  
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  • Rahul

    Thanks for the code.. Logically its correct. The only concern is about adding a 4 digit number to a 3 digit number in regular order

  • Jayce Kim

    I am also curious about that. Did you figure it out?

  • random

    Bunch of looser have you guys tested it once ?
    it wasted my 50 min of time.

  • Zach

    Doesn’t work if first two numbers added together are >= 10 does it?

  • Wonderer

    I wonder, why do you need a new name for l1 and l2 and don’t just use l1 and l2?

  • In this case an additional ListNode is added at the end of resulting sum. The following excerpt solves the case:

    p3.next=new ListNode(1);

  • Mohit

    What if you get 4 digits after adding two 3-digit numbers?