Leetcode – Add Two Numbers (Java)
You are given two linked lists representing two nonnegative numbers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.
Input: (2 > 4 > 3) + (5 > 6 > 4)
Output: 7 > 0 > 8
Java Solution
public class Solution { public ListNode addTwoNumbers(ListNode l1, ListNode l2) { int carry =0; ListNode newHead = new ListNode(0); ListNode p1 = l1, p2 = l2, p3=newHead; while(p1 != null  p2 != null){ if(p1 != null){ carry += p1.val; p1 = p1.next; } if(p2 != null){ carry += p2.val; p2 = p2.next; } p3.next = new ListNode(carry%10); p3 = p3.next; carry /= 10; } if(carry==1) p3.next=new ListNode(1); return newHead.next; } } 
What if the digits are stored in regular order instead of reversed order?
Answer: We can simple reverse the list, calculate the result, and reverse the result.
<pre><code> String foo = "bar"; </code></pre>

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